Use the lens formula 1/f = 1/u + 1/v with the real-is-positive convention, then read the sign of v. Positive v means a real, inverted image. Negative v means a virtual, upright image.
This lesson is part of wave and image interpretation. You can test the same cases in the lens and image-formation explorer.
What are the sign rules?
In the real-is-positive convention, a real object distance u is positive. A real image gives a positive v, and a virtual image gives a negative v. A convex lens has positive f, and a concave lens has negative f.
Decide these signs before you write the formula. Substituting first and deciding the signs later is where errors start.
Worked example 1: object beyond the focal point
A convex lens has f = +10 cm and the object is at u = 15 cm.
- 1/v = 1/f − 1/u = 1/10 − 1/15 = 3/30 − 2/30 = 1/30.
- So v = +30 cm. The positive sign means a real, inverted image.
- Magnification m = v ÷ u = 30 ÷ 15 = 2, so the image is magnified.
The ray diagram agrees: an object between f and 2f gives a real, inverted, magnified image beyond 2f.
Worked example 2: object inside the focal point
Same lens, f = +10 cm, but now u = 6 cm.
- 1/v = 1/10 − 1/6 = 3/30 − 5/30 = −2/30.
- So v = −15 cm. The negative sign means a virtual, upright image on the object’s side.
- m = 15 ÷ 6 = 2.5, so the image is magnified.
This is the magnifying-glass case. The image is larger and upright, and it cannot be projected onto a screen.
Worked example 3: a concave lens
A concave lens has f = −12 cm and the object is at u = 24 cm.
- 1/v = 1/f − 1/u = −1/12 − 1/24 = −2/24 − 1/24 = −3/24 = −1/8.
- So v = −8 cm: virtual, upright.
- m = 8 ÷ 24 = 1/3, so the image is diminished.
A concave lens always gives a virtual, upright, diminished image for a real object, so this result is consistent.
The mistake that costs marks
The usual slip is to drop the negative on a concave lens and use f = +12. Then 1/v = 1/12 − 1/24 = 1/24, so v = +24 cm, and the image looks real and inverted.
That contradicts the ray diagram, which is the warning sign. When the two methods disagree, recheck the sign of f first.
Check yourself
A convex lens has f = +5 cm and an object at u = 20 cm. State v, whether the image is real or virtual, and whether it is magnified or diminished.
Answer
1/v = 1/5 − 1/20 = 4/20 − 1/20 = 3/20, so v = 20/3 ≈ +6.7 cm.
Positive v means the image is real and inverted.
m = (20/3) ÷ 20 = 1/3, so the image is diminished. An object beyond 2f (here 10 cm) gives a real, inverted, diminished image, which matches.
What to study next
Go on to explaining a diffraction comparison, or attempt the integrated practice set.
If you want a teacher to check your signs line by line, see online one-to-one Physics tuition. The mistake log helps you record each sign slip.