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Chemistry · Acids bases and salts

Writing ionic equations with correct charges

The atoms balance in your ionic equation, yet the charges do not.

An ionic equation shows only the particles that change. Write the full equation, split the aqueous ionic compounds, cancel the spectators, then check atoms and charges.

This lesson is part of SPM Chemistry acids, bases and salts. It follows writing neutralisation equations.

What are the four steps?

Work in this order every time.

  1. Write the balanced full equation with state symbols.
  2. Rewrite each (aq) ionic compound as its ions.
  3. Cross out ions that are identical on both sides.
  4. Add up atoms and charges on each side to check.

Worked example 1: a precipitation

Lead(II) nitrate solution reacts with potassium iodide solution.

Full equation: Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)

Split the aqueous compounds: Pb²⁺ + 2NO₃⁻ + 2K⁺ + 2I⁻ → PbI₂(s) + 2K⁺ + 2NO₃⁻

K⁺ and NO₃⁻ appear on both sides, so they are spectators. The ionic equation is Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).

Check: charge on the left is (+2) + 2(−1) = 0, and the right is 0. Atoms are also balanced.

Worked example 2: a metal with acid

Magnesium ribbon reacts with dilute hydrochloric acid. Full equation: Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g).

Split HCl and MgCl₂ into ions: Mg + 2H⁺ + 2Cl⁻ → Mg²⁺ + 2Cl⁻ + H₂. The chloride ions cancel.

The ionic equation is Mg(s) + 2H⁺(aq) → Mg²⁺(aq) + H₂(g). Both sides have a total charge of +2.

The mistake that loses marks

A student writes Pb²⁺ + I⁻ → PbI₂. Count the iodine: one on the left, two on the right. The charge is also wrong, +1 on the left and 0 on the right.

The fix is the coefficient 2 in front of I⁻, which repairs both counts together. A charge check catches this when an atom check alone may not.

Check yourself

Write the ionic equation for barium chloride solution reacting with sodium sulfate solution to give a white precipitate.

Answer

Full equation: BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq).

Split: Ba²⁺ + 2Cl⁻ + 2Na⁺ + SO₄²⁻ → BaSO₄(s) + 2Na⁺ + 2Cl⁻. Cancel Na⁺ and Cl⁻.

Ionic equation: Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s). The charge is 0 on both sides.

What to study next

Put the skill to work in interpreting qualitative analysis observations, where each precipitate has an ionic equation. You can also review planning salt preparation.

The mole and stoichiometry steps tool checks quantities once the equation is right. To have a teacher read your ionic equations with you, see online one-to-one Chemistry tuition.

Common questions

Which substances are written as ions?

Write soluble ionic compounds in solution, (aq), as separate ions. Keep solids, liquids such as water, and gases as whole formulae. Strong acids are also written as ions, for example H⁺ and Cl⁻ for hydrochloric acid.

What is a spectator ion?

A spectator ion appears unchanged on both sides of the equation. It is present in solution but does not take part in the reaction, so it is cancelled out. In a precipitation reaction the ions that stay dissolved are the spectators.

Does the total charge have to be zero?

Not necessarily. The total charge on the left must equal the total charge on the right. For example, Mg + 2H⁺ → Mg²⁺ + H₂ has +2 on each side, and that is correct.

Do I need state symbols?

Yes, they show which substances are split. Write (aq) for aqueous, (s) for solid, (l) for liquid and (g) for gas. A missing state symbol can cost a mark and leaves the reader guessing.

A teacher working one-to-one can check the charge total on each line of your working, which is the step most students skip when marking their own answers.

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