Current is the rate of flow of charge. The relationship I = Q/t links current in amperes, charge in coulombs and time in seconds.
This lesson is part of SPM Physics electricity. The next lesson is applying potential difference, resistance and Ohm’s law.
How do I use I = Q/t?
List the quantities with their units first. Convert anything that is not in amperes, coulombs or seconds, then rearrange.
| Want | Formula | Unit |
|---|---|---|
| Current | I = Q ÷ t | A |
| Charge | Q = I × t | C |
| Time | t = Q ÷ I | s |
Worked example: from current to electrons
A current of 3.0 A flows through a heater element for 40 s. Find the charge, then the number of electrons that pass a point in the element.
- Charge: Q = I × t = 3.0 × 40 = 120 C.
- Electrons: N = Q ÷ e = 120 ÷ (1.6 × 10⁻¹⁹) = 7.5 × 10²⁰.
The second step reuses the charge from the first. Write the unit with each answer: C for charge, and no unit for the number of electrons.
The mistake that loses marks
A current of 0.50 A flows for 2 minutes, and a student writes Q = 0.50 × 2 = 1.0 C. The time was left in minutes.
Convert first: 2 minutes = 120 s, so Q = 0.50 × 120 = 60 C. The wrong answer is 60 times too small, and a units line at the top would have caught it.
Check yourself
A charge of 450 C flows through a lamp in 5.0 minutes. Find the current, and state which unit conversion you made.
Answer
Convert 5.0 minutes to seconds: 5.0 × 60 = 300 s.
I = Q ÷ t = 450 ÷ 300 = 1.5 A.
Check the size: 1.5 coulombs each second over 300 seconds gives 450 coulombs.
What to study next
Current alone does not say how much energy a component transfers. Applying potential difference, resistance and Ohm’s law adds the second quantity, and the units and significant figure checker can check your working.
Test the topic with the electricity practice set. For a teacher to go through your unit conversions with you, see online one-to-one Physics tuition or the one-hour trial class (from RM50).