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Algebra readiness for SPM Maths

Expanding and factorising made simple

You multiply only the first term in the bracket, or cannot see what to factorise.

Expanding multiplies every term inside a bracket by the factor outside. Factorising does the reverse: it pulls a common factor out and leaves a bracket behind.

How does expanding work?

Multiply the outside factor by each term inside, one at a time, keeping signs with their terms.

For example, 3(2x − 5) becomes 3 × 2x and 3 × (−5). That gives 6x − 15.

Test it with x = 4. The original is 3(8 − 5) = 9, and the answer is 24 − 15 = 9.

How does factorising work?

Look for the highest common factor of all terms. Write it outside a bracket, then divide each term by it to fill the bracket.

Take 12x + 18. The highest number dividing both 12 and 18 is 6. Dividing gives 2x and 3, so 12x + 18 = 6(2x + 3).

Check by expanding: 6 × 2x = 12x and 6 × 3 = 18. This works.

Worked example

Take the original expression 4a² − 10a and factorise it.

Step Working
Numbers 4 and 10 share the factor 2
Letters a² and a share the letter a
Common factor 2a
Fill bracket 4a² ÷ 2a = 2a and −10a ÷ 2a = −5
Answer 2a(2a − 5)

Expanding back: 2a × 2a = 4a² and 2a × (−5) = −10a. The check matches the start.

What does the common mistake look like?

A student expands 5(x + 3) as 5x + 3. Only the first term was multiplied. The correct expansion is 5x + 15.

A quick test catches it. Let x = 1. Then 5(1 + 3) = 20, but 5(1) + 3 = 8. Two different answers mean the expansion is wrong.

A similar slip in factorising is taking out a factor that is too small. For 12x + 18, writing 3(4x + 6) is not wrong, but it is incomplete: the bracket still has a common factor of 2. Always check that nothing more can come out.

Steps to follow

  1. To expand, multiply the outside factor by every term inside, signs included.
  2. To factorise, find the highest common factor of the numbers, then any shared letter.
  3. Always check by expanding your factorised answer or substituting a small number.

Self-check

Expand −2(3y − 4) and factorise 15p + 25.

Answer

Expanding: −2 × 3y = −6y and −2 × (−4) = +8, so −6y + 8. Check with y = 1: −2(3 − 4) = 2, and −6 + 8 = 2.

Factorising: the highest common factor of 15 and 25 is 5, so 15p + 25 = 5(3p + 5). Expanding back gives 15p + 25.

Where to go next

Brackets appear in almost every equation, so the next skill is solving a linear equation step by step. If simplifying after expanding causes trouble, revisit collecting like terms. The algebra readiness hub shows the whole sequence.

Common questions

What is the difference between expanding and factorising?

Expanding removes brackets by multiplying: 3(x + 2) becomes 3x + 6. Factorising puts brackets back by taking out a common factor: 3x + 6 becomes 3(x + 2). They are reverse operations of each other.

How do I know what common factor to take out?

Find the largest number that divides every term, then any letter that appears in every term. For 12x + 18 the number is 6, so the factor is 6. Check by expanding your answer back.

Why do I get negative signs wrong when expanding?

A negative outside the bracket changes the sign of every term inside. So −2(x − 3) gives −2x + 6, not −2x − 6. Multiply each term by the whole −2, sign included.

Factorising depends on spotting patterns, which comes from many short, guided tries. In a one-to-one lesson, the teacher picks each next expression at a level that just stretches you.

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