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Additional Mathematics · Differentiation

Applying the chain rule

You can differentiate a power of x, but a bracketed power keeps giving the wrong answer.

The chain rule differentiates a bracket raised to a power. Work from the outside in: differentiate the power, keep the bracket, then multiply by the derivative of the inside.

This lesson is part of SPM Additional Mathematics differentiation. It builds on differentiating powers, products and quotients.

What does the rule say?

If y = (f(x))ⁿ, then dy/dx = n (f(x))ⁿ⁻¹ × f′(x). The last factor is the derivative of the inside.

Another way to write it uses u for the inside: if y is a function of u and u is a function of x, then dy/dx = dy/du × du/dx.

Worked example 1: a bracket to a power

Differentiate y = (3x + 2)⁵.

Outside: the power 5 comes down and the new power is 4, giving 5(3x + 2)⁴. Inside: the derivative of 3x + 2 is 3.

Multiply: dy/dx = 5(3x + 2)⁴ × 3 = 15(3x + 2)⁴.

Worked example 2: a square root

Differentiate y = √(4x − 1).

Rewrite as y = (4x − 1)^(1/2). Outside: (1/2)(4x − 1)^(−1/2). Inside: the derivative of 4x − 1 is 4.

So dy/dx = (1/2)(4x − 1)^(−1/2) × 4 = 2(4x − 1)^(−1/2), which is 2 ÷ √(4x − 1).

Worked example 3: using u

Differentiate y = (x² + 1)³ by setting u = x² + 1.

Then y = u³, so dy/du = 3u², and du/dx = 2x. Multiply: dy/dx = 3u² × 2x = 6x(x² + 1)².

To find the gradient at x = 1, put x = 1: 6(1)(2)² = 24.

The mistake that costs marks

The common slip is to differentiate the outside and forget the inside.

Question Wrong Right
d/dx of (2x + 1)⁴ 4(2x + 1)³ 4(2x + 1)³ × 2 = 8(2x + 1)³

A quick check exposes it. Take (2x + 1)² = 4x² + 4x + 1, which differentiates directly to 8x + 4 = 4(2x + 1).

The chain rule gives 2(2x + 1) × 2 = 4(2x + 1), which matches. Leaving out the inner factor 2 would give 2(2x + 1), exactly half of the correct answer.

Check yourself

Differentiate y = 1 ÷ (2x − 5)², then find the gradient at x = 3.

Answer

Rewrite as y = (2x − 5)^(−2).

dy/dx = −2(2x − 5)^(−3) × 2 = −4(2x − 5)^(−3) = −4 ÷ (2x − 5)³.

At x = 3: 2x − 5 = 1, so the gradient is −4 ÷ 1 = −4.

What to study next

Apply the chain rule to gradients in finding tangents and normals. Practise the rules with the polynomial differentiation tutor, then test yourself on the differentiation practice set.

If you want a teacher to watch where the inner derivative goes missing, see online one-to-one Additional Mathematics tuition.

Common questions

What is the chain rule in simple words?

Differentiate the outer power as if the bracket were a single letter, then multiply by the derivative of what is inside the bracket. In symbols, if y = u^n with u a function of x, then dy/dx = n u^(n−1) × du/dx.

How do I differentiate a square root or a fraction with the chain rule?

Rewrite first. A root becomes a power of one half, and 1 over a bracket becomes the bracket to the power of minus one. Then apply the chain rule in the usual way and simplify at the end.

When do I use the product rule together with the chain rule?

When two factors are multiplied and one of them is a bracket to a power, differentiate the bracket with the chain rule inside the product rule. Take it one factor at a time and write each part before combining.

How can I check my chain-rule answer?

Choose a simple value of x, differentiate numerically using a small change, or expand a low power by hand and compare. For example, expand (x + 1)² first and differentiate it directly to confirm the rule gives the same result.

If the chain rule works on easy brackets but breaks on roots and fractions, a one-to-one teacher can rewrite the expression with you and watch each step.

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