Skip to content
SPM Tuition
Chemistry · Redox equilibrium

Writing and balancing half-equations

You know electrons are involved, but they keep ending up on the wrong side of the arrow.

A half-equation shows just one of the two changes in a redox reaction, with the electrons written in. Two half-equations, balanced for electrons and added together, give the full ionic equation.

This lesson is part of SPM Chemistry redox equilibrium. It builds on identifying oxidation and reduction.

How do you write one half-equation?

Start with the species and what it becomes, then add electrons until the charge is equal on both sides.

  • Oxidation, electrons lost: Mg → Mg²⁺ + 2e⁻.
  • Reduction, electrons gained: Ag⁺ + e⁻ → Ag.

Check the charge on each side. For Mg → Mg²⁺ + 2e⁻ the left side is 0 and the right side is +2 + (−2) = 0.

Worked example: magnesium in silver nitrate

Mg displaces silver from silver nitrate solution.

  1. Oxidation: Mg → Mg²⁺ + 2e⁻ (loses 2 electrons).
  2. Reduction: Ag⁺ + e⁻ → Ag (gains 1 electron).
  3. Equalise electrons: multiply the silver half-equation by 2, giving 2Ag⁺ + 2e⁻ → 2Ag.
  4. Add and cancel 2e⁻ on both sides: Mg + 2Ag⁺ → Mg²⁺ + 2Ag.

Check the charge: left 0 + 2(+1) = +2. Right +2 + 0 = +2. It balances.

Worked example with different electron numbers

Aluminium displaces copper from copper(II) sulfate.

  1. Oxidation: Al → Al³⁺ + 3e⁻.
  2. Reduction: Cu²⁺ + 2e⁻ → Cu.
  3. The lowest common multiple of 3 and 2 is 6, so multiply the first by 2 and the second by 3.
  4. 2Al → 2Al³⁺ + 6e⁻ and 3Cu²⁺ + 6e⁻ → 3Cu.
  5. Add: 2Al + 3Cu²⁺ → 2Al³⁺ + 3Cu.

Charge check: left 3 × (+2) = +6, right 2 × (+3) = +6.

The mistake that costs marks

The common slip is putting the electrons on the wrong side, for example Mg + 2e⁻ → Mg²⁺. The charge test catches it straight away.

Line Left charge Right charge Verdict
Mg + 2e⁻ → Mg²⁺ −2 +2 Not balanced
Mg → Mg²⁺ + 2e⁻ 0 0 Balanced

If the charges do not match, move the electrons or change how many there are.

Check yourself

Zinc is placed in lead(II) nitrate solution and lead forms. Write the two half-equations and the ionic equation.

Answer

Oxidation: Zn → Zn²⁺ + 2e⁻.

Reduction: Pb²⁺ + 2e⁻ → Pb.

Both have two electrons, so add directly: Zn + Pb²⁺ → Zn²⁺ + Pb.

Charge check: left +2, right +2.

What to study next

Half-equations are used in both electrolysis and cells. Continue with predicting electrolysis products and then explaining simple chemical cells. The redox practice set tests all of them.

The mole and stoichiometry steps tool helps with the amount calculations that sometimes follow. If you want a teacher to check your half-equations, see online one-to-one Chemistry tuition.

Common questions

Which side do the electrons go on?

Electrons go on the right side in an oxidation half-equation, because electrons are lost. They go on the left side in a reduction half-equation, because electrons are gained. Remember that the electrons are always on the side that makes the charge balance.

How do I know how many electrons to write?

Use the charge. Make the total charge on the left equal the total charge on the right. For Mg → Mg²⁺, the right side is 2+, so two electrons are added to the right to make the left 0 and the right 0.

Why do I multiply half-equations before adding them?

The electrons lost in oxidation must equal the electrons gained in reduction, because electrons are not left over in the final equation. Multiply each half-equation by a whole number until both have the same number of electrons.

If balanced equations look fine but the electrons sit on the wrong side, a one-to-one Chemistry teacher can check each line and explain how the charge test catches it.

  • Online one-to-one lessons for your child with an experienced teacher.
  • Your first class is a one-hour trial, from RM50. The fee is agreed before you book.
  • Happy with the teacher? Continue with lessons of about 1.5 hours. If not, ask for another teacher.